Figure 1: From a AIII class topological insulator to a BDI topological superconductor.

(a) AIII topological insulator with fermionic end states Ψ1 and Ψ2 located at the ends of the wire. (b) By inducing superconductivity on the AIII class topological insulator, each fermionic end state becomes two MFs and the system becomes a BDI class topological superconductor in the NBDI=2 phase. As the pairing strength Δ increases, one of the Majorana fermions at each end merges into the bulk. (c) After the bulk gap is closed by increasing Δ, only one MF end state is left at each end and we have the NBDI=1 phase. (d) Phase diagram of the BDI class topological superconductor characterized by the topological invariant NBDI as functions of the pairing strength Δ and Γz−2tso.