Table 7 Quantitative analysis for the characteristics of the protection scheme.
Laboratory system instance | Number of scenarios | Malfunction times |
---|---|---|
The total number of trips (correct + incorrect) | 840 | 7 |
The total number of normal operations | 75 | 0 |
Estimation of the characteristics of the protection scheme | Y1 = The total number of experiments = 915 | Malfunction times = 7 |
Y2 = The total number of trips |  = 840 | |
Y3 = The times of correct trips |  = 833 | |
Y4 = The times of tripping failures |  = 8 | |
Y5 = The times of desirable trips |  = 833 + 8 = 841 | |
Y6 = The times of incorrect trips |  = 840 − 833 = 7 | |
Y7 = Y5 + Y6 |  = 841 + 7 = 848 | |
\(D= \frac{Y3 }{Y5}\times 100\) % | = \(\frac{833}{841}\) \(\times\) 100 = \(99.05 \%\) | |
\(S= \frac{Y3}{Y2}\times 100 \%\) | = \(\frac{833}{840}\times\) 100 = \(99.17 \%\) | |
\(R= \frac{Y3}{ Y7}\times 100 \%\) | = \(\frac{833}{848}\times\) 100 = \(98.23 \%\) | |
\(A= \frac{Y1-Y4-Y6}{Y1}\times 100 \%\) | = \(\frac{915-8-7 }{915} \times\) 100 = 98.36% |