Table 1 Comparison of PM and KPM for Lower bound values of example 5.1.

From: A new approach for solving fuzzy non-linear equations using higher order iterative method

Method

\({\underline{x}}(s)\)

n

\({\underline{x}}_{n}\)

\({\underline{f}}({\underline{x}}_{n})\)

\(| {\underline{x}}_{n+1}-{\underline{x}}_{n}|\)

CPU Time

PM

\(s=0\)

1

0.454737

\(6.4\times 10^{-62}\)

\(8.1\times 10^{-63}\)

0.014

2

0.454737

0

0

0.014

KPM

\(s=0\)

3

0.454737

\(1.6\times 10^{-60}\)

\(2.1\times 10^{-61}\)

0.016

4

0.454737

0

0

0.016

PM

\(s=0.2\)

1

0.458277

\(2.22045\times 10^{-16}\)

0

0.014

2

0.458277

0

0

0.014

KPM

\(s=0.2\)

3

0.458277

\(2.22045\times 10^{-16}\)

0

0.016

4

0.458277

0

0

0.016

PM

\(s=0.4\)

1

0.461302

\(2.22045\times 10^{-16}\)

0

0.014

4

0.461302

0

0

0.014

KPM

\(s=0.4\)

3

0.461302

\(2.22045\times 10^{-16}\)

0

0.016

4

0.461302

0

0

0.016

PM

\(s=0.6\)

1

0.463917

\(6.66134\times 10^{-16}\)

\(5.55112\times 10^{-17}\)

0.014

2

0.463917

\(2.22045\times 10^{-16}\)

0

0.014

KPM

\(s=0.6\)

1

0.463917

\(6.66134\times 10^{-16}\)

\(5.55112\times 10^{-17}\)

0.016

4

0.463917

\(2.22045\times 10^{-16}\)

0

0.014

PM

\(s=0.8\)

1

0.466199

\(6.66134\times 10^{-16}\)

\(5.55112\times 10^{-17}\)

0.014

2

0.466199

0

0

0.014

KPM

\(s=0.8\)

3

0.466199

\(6.66134\times 10^{-16}\)

\(5.55112\times 10^{-17}\)

0.016

4

0.466199

0

0

0.016

PM

\(s=1\)

1

0.468209

\(1.4\times 10^{-16}\)

\(1.3\times 10^{-17}\)

0.014

2

0.468209

0

0

0.014

KPM

\(s=1\)

3

0.468209

\(4.1\times 10^{-15}\)

\(3.6\times 10^{-15}\)

0.016

4

0.468209

0

0

0.016