Table 1 Comparison of PM and KPM for Lower bound values of example 5.1.
From: A new approach for solving fuzzy non-linear equations using higher order iterative method
Method | \({\underline{x}}(s)\) | n | \({\underline{x}}_{n}\) | \({\underline{f}}({\underline{x}}_{n})\) | \(| {\underline{x}}_{n+1}-{\underline{x}}_{n}|\) | CPU Time |
|---|---|---|---|---|---|---|
PM | \(s=0\) | 1 | 0.454737 | \(6.4\times 10^{-62}\) | \(8.1\times 10^{-63}\) | 0.014 |
2 | 0.454737 | 0 | 0 | 0.014 | ||
KPM | \(s=0\) | 3 | 0.454737 | \(1.6\times 10^{-60}\) | \(2.1\times 10^{-61}\) | 0.016 |
4 | 0.454737 | 0 | 0 | 0.016 | ||
PM | \(s=0.2\) | 1 | 0.458277 | \(2.22045\times 10^{-16}\) | 0 | 0.014 |
2 | 0.458277 | 0 | 0 | 0.014 | ||
KPM | \(s=0.2\) | 3 | 0.458277 | \(2.22045\times 10^{-16}\) | 0 | 0.016 |
4 | 0.458277 | 0 | 0 | 0.016 | ||
PM | \(s=0.4\) | 1 | 0.461302 | \(2.22045\times 10^{-16}\) | 0 | 0.014 |
4 | 0.461302 | 0 | 0 | 0.014 | ||
KPM | \(s=0.4\) | 3 | 0.461302 | \(2.22045\times 10^{-16}\) | 0 | 0.016 |
4 | 0.461302 | 0 | 0 | 0.016 | ||
PM | \(s=0.6\) | 1 | 0.463917 | \(6.66134\times 10^{-16}\) | \(5.55112\times 10^{-17}\) | 0.014 |
2 | 0.463917 | \(2.22045\times 10^{-16}\) | 0 | 0.014 | ||
KPM | \(s=0.6\) | 1 | 0.463917 | \(6.66134\times 10^{-16}\) | \(5.55112\times 10^{-17}\) | 0.016 |
4 | 0.463917 | \(2.22045\times 10^{-16}\) | 0 | 0.014 | ||
PM | \(s=0.8\) | 1 | 0.466199 | \(6.66134\times 10^{-16}\) | \(5.55112\times 10^{-17}\) | 0.014 |
2 | 0.466199 | 0 | 0 | 0.014 | ||
KPM | \(s=0.8\) | 3 | 0.466199 | \(6.66134\times 10^{-16}\) | \(5.55112\times 10^{-17}\) | 0.016 |
4 | 0.466199 | 0 | 0 | 0.016 | ||
PM | \(s=1\) | 1 | 0.468209 | \(1.4\times 10^{-16}\) | \(1.3\times 10^{-17}\) | 0.014 |
2 | 0.468209 | 0 | 0 | 0.014 | ||
KPM | \(s=1\) | 3 | 0.468209 | \(4.1\times 10^{-15}\) | \(3.6\times 10^{-15}\) | 0.016 |
4 | 0.468209 | 0 | 0 | 0.016 |