Figure 5
Realization of the quantum pendulum.
(a) Full BdG calculation of the LDOS vs. energy in θ = π location on the ring (of width W = ξ and radius R = 5ξ), for the quantum rotor (no current) and pendulum state (with current generated via ∂φ/∂y = 0.0033/a). The 2D LDOS for a quantum pendulum is shown for E/Δ = −0.088 in the absence (b) and presence (c) of a small perpendicular magnetic field, Φ/Φ0 = 0.15.
