Table 2 indicates the chemical composition and the method of calculation of YS and US for the test samples.
Symbol | Chemical composition | Density (ρ) \(\rho =m/V\) and Dimensions | The measured Time of flight (tTOF) Sec | PTC calculations | YScalculated (MPa) | UScalculated (MPa) |
|---|---|---|---|---|---|---|
A Non- ferromagnetic | Al-4.5 Cu-0.85Si-0.7 Fe-0.5Mg-0.25Zn Aluminum alloys (T4) | \(\rho =2800kg/{m}^{3}\) \(D=9mm\) \(L=63mm\) | \(\begin{aligned}&(30-9)\times {10}^{-6}\\& =21\times {10}^{-6}\end{aligned}\) | \({C}_{L}=\frac{L\times 2}{t}=\frac{0.063\times 2}{21\times {10}^{-6}}\) \({C}_{L} =6000\) \(Z={C}_{L}\times \rho =16.8\times {10}^{6}\) In Eq. (2) \(PTC=\) \(\frac{\left(39.9\times 16.8\right)}{\left(1.5+16.8\right)\left(16.8+9.9761\right)}\) \(PTC=1.368\) | 424.8 (In Eq. (3) because it is Non-ferromagnetic) | 480.6 (In Eq. (4) because it is Non-ferromagnetic) |
B Non- ferromagnetic | Cu-7Sn-5 Al-3 Ni-0.7 Fe-0.5Zn | \(\rho =7370kg/{m}^{3}\) \(D=7mm\) \(L=170mm\) | \(\begin{aligned}&(92-9)\times {10}^{-6}\\&=83\times {10}^{-6}\end{aligned}\) | \({C}_{L}=\frac{L\times 2}{t}=\frac{0.170\times 2}{83\times {10}^{-6}}\) \({C}_{L} =4096m/s\) \(Z={C}_{L}\times \rho =30.1\times {10}^{6}\) In Eq. (2) \(PTC=\) \(\frac{\left(39.9\times 30.1\right)}{\left(1.5+30.1\right)\left(30.1+9.97\right)}\) \(PTC=0.946\) | 448 (In Eq. (3) because it is Non- ferromagnetic) | 487 (In Eq. (4) because it is Non- ferromagnetic) |
C Non- ferromagnetic | 60 Cu-39.25Zn-0.75Sn Naval brass | \(\rho =8400kg/{m}^{3}\) \(D=0.007mm\) \(L=79mm\) | \(\begin{aligned}&=(12.2-9)\times {10}^{-6}\\&=3.2\times {10}^{-6}\end{aligned}\) | \({C}_{L}=\frac{D\times 2}{t}=\frac{0.007\times 2}{3.2\times {10}^{-6}}\) \({C}_{L} =4375\) \(Z={C}_{L}\times \rho =36.75\times {10}^{6}\) In Eq. (2) \(PTC=\) \(\frac{\left(39.9\times 36.75\right)}{\left(1.5+36.75\right)\left(36.75+9.97\right)}\) \(PTC=0.82\) | 469 (In Eq. (3) because it is Non- ferromagnetic) | 569 (In Eq. (4) because it is Non- ferromagnetic) |
D Nickel- ferromagnetic | 60.5 Ni-23 Cr-14 Fe-1.5 Al-1 Cu Inconel® 601 | \(\rho =8450kg/{m}^{3}\) \(D=8mm\) \(L=55mm\) | \(\begin{aligned}&=(28-9)\times {10}^{-6}\\&=19\times {10}^{-6}\end{aligned}\) | \({C}_{L}=\frac{L\times 2}{t}=\frac{0.055\times 2}{19\times {10}^{-6}}\) \({C}_{L} =5789\) \(Z={C}_{L}\times \rho =48.9\times {10}^{6}\) In Eq. (2) \(PTC=\) \(\frac{\left(39.9\times 48.9\right)}{\left(1.5+48.9\right)\left(48.9+9.97\right)}\) \(PTC=0.657\) | 409 (In Eq. (5) because it is Nickel- ferromagnetic) | 720 (In Eq. (6) because it is Nickel- ferromagnetic) |
E Nickel- ferromagnetic | 46 Fe-32.5 Ni-21 Cr-0.4 Al-0.35 Ti-0.05 C Incoloy® 800 | \(\rho =8530kg/{m}^{3}\) \(D=10mm\) \(L=198mm\) | \(\begin{aligned}&=(79-9)\times {10}^{-6}\\&=70\times {10}^{-6}\end{aligned}\) | \({C}_{L}=\frac{L\times 2}{t}=\frac{0.198\times 2}{70\times {10}^{-6}}\) \({C}_{L} =5657\) \(Z={C}_{L}\times \rho =48.2\times {10}^{6}\) In Eq. (2) \(PTC=\) \(\frac{\left(39.9\times 48.2\right)}{\left(1.5+48.2\right)\left(48.2+9.97\right)}\) \(PTC=0.665\) | 389 (In Eq. (5) because it is Nickel- ferromagnetic) | 685 (In Eq. (6) because it is Nickel- ferromagnetic) |
F plain carbon steel and low-alloy steel | 98.03 Fe-1.3Mn-0.14 C-0.072S-0.04P G11180 | \(\rho =7750kg/{m}^{3}\) \(D=7mm\) \(L=110mm\) | \(\begin{aligned}&=(53-9)\times {10}^{-6}\\&=44\times {10}^{-6}\end{aligned}\) | \({C}_{L}=\frac{L\times 2}{t}=\frac{0.11\times 2}{44\times {10}^{-6}}\) \({C}_{L} =5000\) \(Z={C}_{L}\times \rho =38.75\times {10}^{6}\) In Eq. (2) \(PTC=\) \(\frac{\left(39.9\times 38.75\right)}{\left(1.5+38.75\right)\left(38.75+9.97\right)}\) \(PTC=0.788\) | 293 (In Eq. (7) because it is plain carbon steel and low-alloy steel | 525 (In Eq. (8) because it is plain carbon steel and low-alloy steel |
G plain carbon steel and low-alloy steel | 97.3 Fe-1.9Mn-0.38 C-0.35Si-0.04S-0.035P AISI1340 | \(\rho =7750kg/{m}^{3}\) \(D=9mm\) \(L=53mm\) | \(\begin{aligned}&=(26.8-9)\times {10}^{-6}\\&=17.8\times {10}^{-6}\end{aligned}\) | \({C}_{L}=\frac{L\times 2}{t}=\frac{0.053\times 2}{17.8\times {10}^{-6}}\) \({C}_{L} =5955\) \(Z={C}_{L}\times \rho =46.1\times {10}^{6}\) In Eq. (2) \(PTC=\) \(\frac{\left(39.9\times 46.1\right)}{\left(1.5+46.1\right)\left(46.1+9.97\right)}\) \(PTC=0.689\) | 475 (In Eq. (7) because it is plain carbon steel and low-alloy steel | 725 (In Eq. (8) because it is plain carbon steel and low-alloy steel |
