Fig. 12: Comparison of the relaxation time to the viscosity in the Kob-Andersen (KA) model. | Communications Physics

Fig. 12: Comparison of the relaxation time to the viscosity in the Kob-Andersen (KA) model.

From: Universal mechanism of shear thinning in supercooled liquids

Fig. 12

a \({\tau }_{\alpha }(T,\dot{\gamma })/{\tau }_{\alpha 0}(T),\,\eta (T,\dot{\gamma })/{\eta }_{0}(T)\) and b \(\left[{\tau }_{\alpha }(T,\dot{\gamma })/{\tau }_{\alpha 0}(T)\right]/{\dot{\gamma }}^{-\nu },\,\left[\eta (T,\dot{\gamma })/{\eta }_{0}(T)\right]/{\dot{\gamma }}^{-\nu }\) are plotted as a function of \(\dot{\gamma }/{\dot{\gamma }}_{c}\). Circles and squares represent values of τα and η, respectively. The temperature is T = 0.45. Black line indicates τα/τα0, η/η0 = 1, wheares blue line indicates \({\tau }_{\alpha }/{\tau }_{\alpha 0},\,\eta /{\eta }_{0}\propto {(\dot{\gamma }/{\dot{\gamma }}_{c})}^{-\nu }\) with ν 0.71. The vertical dotted line indicates the location of \({\dot{\gamma }}_{c}\).

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